write the IUPAC name of the compound
`NH_(2)-underset(HOOC)underset(|)(CH)-underset(" "COOH)underset(|)(CH)-CHO`

Explanation

To write the IUPAC name of the given compound, we will follow a systematic approach:

### Step 1: Identify the Functional Groups
The compound contains three types of functional groups:
- Carboxylic acid (-COOH)
- Amine (-NH₂)
- Aldehyde (-CHO)

### Step 2: Determine the Principal Functional Group
Among these functional groups, carboxylic acids have the highest priority for naming. Therefore, we will consider the carboxylic acid as the principal functional group.

### Step 3: Number the Carbon Chain
We will start numbering the carbon chain from the end nearest to the carboxylic acid group to give it the lowest possible number.

- The numbering will be as follows:
1. COOH (Carboxylic acid)
2. NH₂ (Amine)
3. CHO (Aldehyde)

The numbering will be:
1. COOH
2. NH₂
3. CHO

### Step 4: Identify the Carbon Chain Length
Counting the carbon atoms in the longest continuous chain gives us a total of four carbon atoms. Therefore, the base name will be derived from butane.

### Step 5: Identify the Substituents and Their Positions
- The amine group (-NH₂) is located at position 2, so we will denote it as "2-amino".
- The aldehyde group (-CHO) is located at position 3, so we will denote it as "3-formyl".
- The carboxylic acid groups at the ends will be denoted as "butanedioic acid" since there are two carboxylic acid groups.

### Step 6: Combine the Names
Now we can combine all parts to form the complete IUPAC name. The substituents are listed in alphabetical order:
- "2-amino"
- "3-formyl"
- "butanedioic acid"

### Final IUPAC Name
Putting it all together, the IUPAC name of the compound is:
**2-amino-3-formyl-butanedioic acid**

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