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A ball of mass 200g was thrown with the ...

A ball of mass 200g was thrown with the velocity of 50m/s. The de Broglie wavelength is:

A

`6.6xx10^(-34)`m

B

`6.6xx10^(-35)`m

C

`6.6xx10^(-33)`m

D

All of these

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The correct Answer is:
To find the de Broglie wavelength of a ball with a mass of 200 g thrown at a velocity of 50 m/s, we can follow these steps: ### Step-by-Step Solution: 1. **Convert Mass to Kilograms**: The mass of the ball is given as 200 grams. To convert grams to kilograms, we use the conversion factor: \[ \text{mass in kg} = \text{mass in g} \times \frac{1 \text{ kg}}{1000 \text{ g}} = 200 \text{ g} \times 10^{-3} = 0.2 \text{ kg} \] 2. **Identify the Velocity**: The velocity of the ball is given as: \[ v = 50 \text{ m/s} \] 3. **Use the de Broglie Wavelength Formula**: The de Broglie wavelength (\(\lambda\)) is given by the formula: \[ \lambda = \frac{h}{mv} \] where: - \(h\) is Planck's constant, approximately \(6.626 \times 10^{-34} \text{ Js}\), - \(m\) is the mass of the object in kg, - \(v\) is the velocity in m/s. 4. **Substitute the Values into the Formula**: Now we substitute the values into the formula: \[ \lambda = \frac{6.626 \times 10^{-34} \text{ Js}}{0.2 \text{ kg} \times 50 \text{ m/s}} \] 5. **Calculate the Denominator**: First, calculate the denominator: \[ 0.2 \text{ kg} \times 50 \text{ m/s} = 10 \text{ kg m/s} \] 6. **Calculate the Wavelength**: Now substitute this back into the equation for \(\lambda\): \[ \lambda = \frac{6.626 \times 10^{-34}}{10} = 6.626 \times 10^{-35} \text{ m} \] 7. **Final Result**: Therefore, the de Broglie wavelength of the ball is: \[ \lambda \approx 6.626 \times 10^{-35} \text{ m} \]

To find the de Broglie wavelength of a ball with a mass of 200 g thrown at a velocity of 50 m/s, we can follow these steps: ### Step-by-Step Solution: 1. **Convert Mass to Kilograms**: The mass of the ball is given as 200 grams. To convert grams to kilograms, we use the conversion factor: \[ \text{mass in kg} = \text{mass in g} \times \frac{1 \text{ kg}}{1000 \text{ g}} = 200 \text{ g} \times 10^{-3} = 0.2 \text{ kg} ...
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