Compound `C_(5)H_(10) (A)underset((2) Me_(2)S//H_(2)O)overset((1)O_(3))rarrB+C`
Compound B and C both gives iodoform test and B also give silver mirror with ammonical silver nitrate. The structure of compound A is `:`

Options

A. `M//4`
B. `M//8`
C. `M//1`
D. `M//2`

Explanation

To find the structure of compound A (C₅H₁₀), we will analyze the information provided step by step.

### Step 1: Identify the reaction type
The reaction described involves ozonolysis, which is a reaction of alkenes with ozone (O₃) followed by a reductive workup (in this case, with dimethyl sulfide, Me₂S, and water). This typically breaks the double bond in alkenes and forms carbonyl compounds (aldehydes and/or ketones).

**Hint:** Ozonolysis is used to cleave double bonds in alkenes to form carbonyl compounds.

### Step 2: Determine the products
From the information given, compound A (C₅H₁₀) produces two products, B and C, upon ozonolysis. Both products B and C give the iodoform test, which indicates that they contain a methyl ketone or a methyl group adjacent to a carbonyl group.

**Hint:** The iodoform test is indicative of the presence of a methyl ketone (RCOCH₃) or a secondary alcohol that can be oxidized to a methyl ketone.

### Step 3: Analyze the properties of compound B
Compound B gives a silver mirror with ammoniacal silver nitrate, which suggests that it is an aldehyde. Aldehydes can reduce silver ions to metallic silver, forming a mirror on the surface of the test tube.

**Hint:** Aldehydes are typically oxidized to carboxylic acids and can reduce silver ions, leading to the formation of a silver mirror.

### Step 4: Propose the structure of compound A
Given that compound A is an alkene (C₅H₁₀) and considering the ozonolysis products, we can deduce that compound A must be a branched alkene that can yield both an aldehyde and a ketone.

The structure of compound A can be proposed as 2-methyl-2-butene (CH₃C(CH₃)=C(CH₃)CH₂). When ozonolysis occurs, it will yield:
- Compound B: Ethanal (acetaldehyde, CH₃CHO)
- Compound C: 2-pentanone (CH₃COCH₂CH₃)

**Hint:** Look for branched alkenes that can yield both aldehydes and ketones upon ozonolysis.

### Step 5: Confirm the structures of B and C
- **Compound B (ethanal)**: This compound gives the iodoform test and is an aldehyde, confirming it can produce a silver mirror.
- **Compound C (2-pentanone)**: This compound also gives the iodoform test as it contains a methyl ketone group.

**Hint:** Verify that both products meet the criteria for the iodoform test.

### Conclusion
Thus, the structure of compound A is 2-methyl-2-butene.

### Final Answer:
The structure of compound A is 2-methyl-2-butene (C₅H₁₀).

---