The conversion of `Cl-CH=CH-Cl` to `CHCl_(2)-CHCl_(2)` can be carried out with `,`

Options

A. `HCl("excess")`
B. `Cl_(2)//hv`
C. `Cl_(2)//C Cl_(4)`
D. `Cl_(2)//NaOH`

Explanation

To convert `Cl-CH=CH-Cl` to `CHCl2-CHCl2`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Starting Compound**:
We start with `Cl-CH=CH-Cl`, which is a dichloroalkene.

2. **Choose the Correct Reagent**:
We need to select a reagent that can add chlorine across the double bond. The reagent that can achieve this is `Cl2` in the presence of a solvent like `CCl4`.

3. **Reaction Mechanism**:
- When `Cl2` is added to `Cl-CH=CH-Cl`, the double bond will react with the chlorine molecule.
- The double bond will break, and each carbon atom involved in the double bond will bond with a chlorine atom.

4. **Formation of the Product**:
- The addition of chlorine will lead to the formation of `Cl-CH(Cl)-CH(Cl)-Cl`, which simplifies to `CHCl2-CHCl2`.
- This is the desired product.

5. **Conclusion**:
The conversion of `Cl-CH=CH-Cl` to `CHCl2-CHCl2` can be effectively carried out using `Cl2` in the presence of `CCl4`.

### Final Answer:
The conversion can be carried out with `Cl2` in the presence of `CCl4`.

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