Draw structure for n-pentyl bromide

Explanation

To draw the structure for n-pentyl bromide, follow these steps:

### Step-by-Step Solution:

1. **Identify the Alkyl Group**:
- The term "n-pentyl" indicates that we are dealing with a straight-chain alkyl group that consists of 5 carbon atoms. The prefix "n-" signifies that it is a normal (straight-chain) alkane.

2. **Draw the Carbon Backbone**:
- Start by drawing a straight chain of 5 carbon atoms. This can be represented as:
```
C - C - C - C - C
```

3. **Add Hydrogen Atoms**:
- Each carbon in the alkane will be bonded to enough hydrogen atoms to satisfy the tetravalency of carbon (4 bonds per carbon).
- For n-pentyl (C5H11), the structure will look like this:
```
CH3 - CH2 - CH2 - CH2 - CH2
```

4. **Introduce the Bromine Atom**:
- Since we are dealing with n-pentyl bromide, we need to replace one of the hydrogen atoms with a bromine atom (Br).
- Typically, the bromine is attached to the terminal carbon (the first carbon in this case). The structure now becomes:
```
CH2Br - CH2 - CH2 - CH2 - CH3
```

5. **Final Structure**:
- The final structure of n-pentyl bromide can be represented as:
```
CH3 - CH2 - CH2 - CH2 - CH2Br
```

### Final Representation:
```
CH3
|
CH2 - CH2 - CH2 - CH2Br
```