`1-`Phenyl ethanol can be prepared by the reaction of `C_(6)H_(5)CHO` with `:`

Options

A. `CH_(3)Mgl,` ether followed by hydrolysis
B. `C_(2)H_(5)Br+H_(2)O`
C. `CH_(3)CH_(2)Br+`Alc.`KOH`
D. `CH_(2)Br+Al_(4)C_(3)`

Answer

To prepare 1-phenyl ethanol from benzaldehyde (C6H5CHO), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The starting compound is benzaldehyde (C6H5CHO), which contains an aldehyde functional group.

2. **Choose the Grignard Reagent**: To convert the aldehyde into an alcohol, we need a Grignard reagent. In this case, we can use methyl iodide (CH3I) in the presence of magnesium (Mg) to form the Grignard reagent, methylmagnesium iodide (CH3MgI).

3. **Formation of the Grignard Reagent**: The reaction of methyl iodide with magnesium in dry ether will produce the Grignard reagent:
\[ CH3I + Mg \rightarrow CH3MgI \]

4. **Reaction with Benzaldehyde**: The Grignard reagent (CH3MgI) will react with benzaldehyde (C6H5CHO). The nucleophilic carbon of the Grignard reagent attacks the electrophilic carbon of the carbonyl group in benzaldehyde:
\[ C6H5CHO + CH3MgI \rightarrow C6H5CH(OMgI)CH3 \]

5. **Hydrolysis**: After the reaction, we will perform hydrolysis to convert the alkoxide intermediate into the corresponding alcohol. This is done by adding water (H2O):
\[ C6H5CH(OMgI)CH3 + H2O \rightarrow C6H5CH(OH)CH3 + Mg(OH)I \]

6. **Final Product**: The final product of this reaction is 1-phenyl ethanol (C6H5CH(OH)CH3).

### Summary of the Reaction:
- Benzaldehyde (C6H5CHO) reacts with methyl iodide (CH3I) in the presence of magnesium (Mg) to form a Grignard reagent (CH3MgI).
- This Grignard reagent then reacts with benzaldehyde, followed by hydrolysis to yield 1-phenyl ethanol.

### Final Answer:
1-Phenyl ethanol can be prepared by the reaction of C6H5CHO (benzaldehyde) with CH3MgI (methylmagnesium iodide) followed by hydrolysis.

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