`CHCl_(3)+OH^(-)rarrHCOO^(-), `intermediate of this reaction can be

Options

A. `: C Cl_(3)^(-)`
B. `: C Cl_(2)`
C. Both `(1)` and `(2)`
D. can not be predicted

Explanation

To solve the question regarding the intermediate formed in the reaction of chloroform (CHCl₃) with hydroxide ion (OH⁻) leading to the formation of formate ion (HCOO⁻), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in the reaction are chloroform (CHCl₃) and hydroxide ion (OH⁻).

2. **Initial Reaction**:
- The hydroxide ion acts as a base and abstracts a proton (H⁺) from chloroform. This results in the formation of a chloroform anion (CCl₃⁻):
\[ CHCl_3 + OH^- \rightarrow CCl_3^- + H_2O \]

3. **Formation of an Unstable Intermediate**:
- The chloroform anion (CCl₃⁻) is unstable because the negative charge is not well stabilized. This instability leads to the loss of a chloride ion (Cl⁻):
\[ CCl_3^- \rightarrow CCl_2 + Cl^- \]
- The resulting species is a carbene (CCl₂), which is a reactive intermediate.

4. **Hydrolysis of the Carbene**:
- The carbene (CCl₂) can undergo hydrolysis in the presence of water (H₂O) and hydroxide ion (OH⁻). This reaction leads to the formation of the formate ion (HCOO⁻):
\[ CCl_2 + H_2O \rightarrow HCOO^- + HCl \]

5. **Conclusion**:
- The intermediate formed in the reaction is the carbene (CCl₂).

### Final Answer:
The intermediate of the reaction is **CCl₂ (carbene)**.

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