Starting from propanoic acid, the following reaction were carried acid `overset(SOCl_2)toXoverset(NH_3)toYoverset(Br_2+KOH)toZ` What is the compound?

Options

A. `CH_(3)-CH_(2)-Br`
B. `CH_(3)-CH_(2)-NH_(2)`
C.
D. `CH_(3)-CH_(2)-CH_(2)-NH_(2)`

Explanation

To solve the problem step-by-step, we will analyze each reaction starting from propanoic acid.

### Step 1: Reaction of Propanoic Acid with Thionyl Chloride (SOCl₂)

1. **Starting Material**: Propanoic acid (CH₃CH₂COOH).
2. **Reaction**: When propanoic acid reacts with thionyl chloride (SOCl₂), it undergoes a conversion to form an acyl chloride.
3. **Product Formation**: The hydroxyl (-OH) group of propanoic acid is replaced by a chlorine atom, resulting in the formation of propanoyl chloride (CH₃CH₂COCl).

**Chemical Equation**:
\[ \text{CH}_3\text{CH}_2\text{COOH} + \text{SOCl}_2 \rightarrow \text{CH}_3\text{CH}_2\text{COCl} + \text{SO}_2 + \text{HCl} \]

### Step 2: Reaction of Propanoyl Chloride with Ammonia (NH₃)

1. **Starting Material**: Propanoyl chloride (CH₃CH₂COCl).
2. **Reaction**: When propanoyl chloride reacts with ammonia (NH₃), the chlorine atom is replaced by an amine group (-NH₂).
3. **Product Formation**: This results in the formation of propanamide (CH₃CH₂CONH₂).

**Chemical Equation**:
\[ \text{CH}_3\text{CH}_2\text{COCl} + \text{NH}_3 \rightarrow \text{CH}_3\text{CH}_2\text{CONH}_2 + \text{HCl} \]

### Step 3: Reaction of Propanamide with Bromine and KOH (Hofmann Reaction)

1. **Starting Material**: Propanamide (CH₃CH₂CONH₂).
2. **Reaction**: When propanamide is treated with bromine (Br₂) in the presence of potassium hydroxide (KOH), it undergoes the Hofmann degradation reaction.
3. **Product Formation**: This reaction results in the removal of the carbonyl group (C=O) and the formation of an amine. The final product is ethylamine (CH₃CH₂NH₂).

**Chemical Equation**:
\[ \text{CH}_3\text{CH}_2\text{CONH}_2 + \text{Br}_2 + \text{KOH} \rightarrow \text{CH}_3\text{CH}_2\text{NH}_2 + \text{KBr} + \text{H}_2\text{O} \]

### Final Product

The final compound Z obtained from the series of reactions starting from propanoic acid is **ethylamine (CH₃CH₂NH₂)**.

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