An optically inactive amine `(A)` is methylated with excess of `CH_(3)I` and there after reacted with `AgOH` to form alkene `(B)`. The alkene B after ozonolysis gives `HCHO` and `CH_(3)CH_(2)CH_(2)CHO`. A and B in the reaction are respectively.

Options

A. `CH_(3)-CH_(2)-CH_(2)-NH_(2)" "&" "CH_(3)-CH_(2)-CH=CH_(2)`
B. `CH_(3)-CH_(2)-underset(underset(NH_(2))|)(C)H-CH_(2)-CH_(2)" "&" "CH_(3)-CH_(2)-CH=CH-CH_(3)`
C. `CH_(3)-CH_(2)-CH_(2)-CH_(2)-NH_(2)" "&" "CH_(3)-CH_(2)-CH_(2)-CH=CH_(2)`
D. `CH_(3)-CH_(2)-CH_(2)-underset(underset(NH_(2))|)(C)H-CH_(3)" "&" "CH_(3)-CH_(2)-CH_(2)-CH=CH_(2)`

Explanation

To solve the problem, we need to identify the compounds A and B based on the information provided. Here’s a step-by-step breakdown of the solution:

### Step 1: Understanding the Reaction
The problem states that an optically inactive amine (A) is methylated with excess of CH₃I. Methylation typically involves the addition of a methyl group to the amine, which can lead to the formation of a quaternary ammonium salt.

### Step 2: Identifying Alkene (B)
After methylation, the compound is reacted with AgOH, which suggests a dehydrohalogenation reaction that leads to the formation of an alkene (B). The ozonolysis of alkene (B) gives formaldehyde (HCHO) and butanal (CH₃CH₂CH₂CHO).

### Step 3: Analyzing the Ozonolysis Products
The ozonolysis products are HCHO and CH₃CH₂CH₂CHO. The presence of these products indicates that the original alkene (B) must have a structure that, when cleaved, results in these aldehydes.

### Step 4: Constructing Alkene (B)
The ozonolysis suggests that alkene (B) is likely 1-pentene (CH₂=CH-CH₂-CH₂-CH₃). This structure, when ozonolyzed, would yield:
- HCHO from the terminal carbon (C1)
- CH₃CH₂CH₂CHO from the other end (C5)

### Step 5: Identifying Amine (A)
Since we know that amine (A) is optically inactive, it cannot have a chiral center. The simplest amine that can lead to 1-pentene upon methylation and subsequent reaction with AgOH is butylamine (C₄H₉NH₂).

### Conclusion
Thus, the compounds are:
- **Compound A (Optically inactive amine)**: Butylamine (C₄H₉NH₂)
- **Compound B (Alkene)**: 1-Pentene (C₅H₁₀)

### Final Answer
A and B in the reaction are respectively:
- A: Butylamine
- B: 1-Pentene