Identify the correct statement.

Options

A.
B.
C. A is more basic than B
D.

Explanation

To solve the question of identifying the correct statement regarding the basicity of nitrogen-containing compounds, let's analyze each option step by step.

### Step 1: Analyze Option 1
**Statement**: Pyrol is more basic than pyridine.

- **Explanation**: Pyrrole has a nitrogen atom with a lone pair that is involved in resonance with the aromatic ring. This means the lone pair is less available for donation, making pyrrole less basic than pyridine, where the lone pair on nitrogen is not involved in resonance and is more available for donation.
- **Conclusion**: This statement is **incorrect**.

**Hint**: Consider the role of resonance in determining the availability of lone pairs for donation.

### Step 2: Analyze Option 2
**Statement**: Pyridine is more basic than piperidine.

- **Explanation**: Piperidine has a nitrogen atom that is sp³ hybridized, which means its lone pair is more available for donation compared to pyridine's sp² hybridized nitrogen, which has a higher s-character and is less basic.
- **Conclusion**: This statement is **incorrect**.

**Hint**: Remember that hybridization affects the basicity; sp³ hybridized nitrogen is generally more basic than sp².

### Step 3: Analyze Option 3
**Statement**: A is more basic than B.

- **Explanation**: In this context, if A is a nitrogen atom whose lone pair is not in conjugation with pi electrons, it is more available for donation. In contrast, B's lone pair is in conjugation, making it less available for donation. Therefore, A is indeed more basic than B.
- **Conclusion**: This statement is **correct**.

**Hint**: Look at the electronic environment around the nitrogen atoms to determine their basicity.

### Step 4: Analyze Option 4
**Statement**: In case of nicotine, NA is more basic than NB.

- **Explanation**: In nicotine, NA is sp² hybridized, while NB is sp³ hybridized. The sp³ hybridized nitrogen (NB) has a lone pair that is more available for donation compared to the sp² hybridized nitrogen (NA), making NB more basic than NA.
- **Conclusion**: This statement is **incorrect**.

**Hint**: Compare the hybridization states of the nitrogen atoms in nicotine to assess their basicity.

### Final Conclusion
After analyzing all options, the correct statement is **Option 3: A is more basic than B**.