`V.P.` of solute containing `6gm` of non volatile solute in `180gm` of water is `20 "Torr"//mm` of `Hg`. If `1` mole water is further added in to the `V.P.` increase by `0.02`. Torr calculate `V.P.` of pure water `&` molecular of non volatile solute.

Explanation

To solve the problem, we need to calculate the vapor pressure of pure water (P₀) and the molecular weight of the non-volatile solute. We'll use the information provided and apply Raoult's law and the concept of vapor pressure lowering.

### Step 1: Identify the given data
- Mass of non-volatile solute (W) = 6 g
- Mass of solvent (water) = 180 g
- Initial vapor pressure of the solution (Pₛ) = 20 Torr
- Increase in vapor pressure when 1 mole of water is added = 0.02 Torr

...