`1 Lit`. Of aq. Solution of urea having density`=1.060gm//mL` is found to have `DeltaT_(b)=0.5^(@)C`, if temp. of this solution increase to `101.5^(@)C` then calculate amount of water which must have gone is vapour state upto this pt. given `K_(b)=0.5K kg mol^(-1)` for water . Mass of Solution = 1060 gm

Explanation

To solve the problem step by step, we will follow the logical sequence presented in the video transcript.

### Step-by-Step Solution:

1. **Understand the given data:**
- Density of the solution = 1.060 g/mL
- Volume of the solution = 1 L = 1000 mL
- Mass of the solution = Density × Volume = 1.060 g/mL × 1000 mL = 1060 g
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