If boiling point of an aqueous solution is `100.1^(@)C`. What is its freezing point? Given latent heat of fusion and vaporization of water are `80calg^(-1)` and `540 calg^(-1)` respectively.

Explanation

To solve the problem, we need to find the freezing point of an aqueous solution given its boiling point and the latent heats of fusion and vaporization of water. Here’s a step-by-step solution:

### Step 1: Identify the given data
- Boiling point of the solution, \( T_b = 100.1^\circ C \)
- Latent heat of fusion of water, \( L_f = 80 \, \text{cal/g} \)
- Latent heat of vaporization of water, \( L_v = 540 \, \text{cal/g} \)

### Step 2: Calculate the elevation in boiling point
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