`Ba^(2+)` ions, `CN^(-) & Co^(2+)` ions form a water soluble complex with `Ba^(2+)` ions as free cations for a `0.01M` solution of this complex, osmotic pressure `=0.984` atm `&` degree of dissociation `=75%`. Then find ccordination number of `Co^(2+)` ion in this complex (`T=300K, R=0.082L "mol"^(-1) K^(-1)`)

Explanation

To solve the problem, we need to find the coordination number of the `Co^(2+)` ion in the complex formed with `Ba^(2+)` ions and `CN^(-)` ions. We are given the following information:

- Concentration of the complex solution, \( C = 0.01 \, M \)
- Osmotic pressure, \( \pi = 0.984 \, atm \)
- Degree of dissociation, \( \alpha = 75\% = 0.75 \)
- Temperature, \( T = 300 \, K \)
- Ideal gas constant, \( R = 0.082 \, L \, mol^{-1} \, K^{-1} \)

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