On mixing `10 mL` of acetone with `40 mL` of chloroform,the total volume of the solution is

Explanation

To solve the problem of finding the total volume of a solution when mixing 10 mL of acetone with 40 mL of chloroform, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the volumes of the components**:
- Volume of acetone = 10 mL
- Volume of chloroform = 40 mL

2. **Calculate the total volume before considering interactions**:
- Total volume = Volume of acetone + Volume of chloroform
- Total volume = 10 mL + 40 mL = 50 mL

3. **Consider the interactions between the components**:
- When acetone and chloroform are mixed, they may interact through hydrogen bonding. This interaction can lead to a decrease in the total volume of the solution compared to the calculated total volume.

4. **Conclusion about the actual volume**:
- Due to the interactions (hydrogen bonding), the actual volume of the mixture will be less than 50 mL.

### Final Answer:
The total volume of the solution after mixing 10 mL of acetone with 40 mL of chloroform is less than 50 mL.

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