Dry air was passed successively through a solution of `5 g` of a solute in `180 g` of water and then through pure water. The loss in the weight of solution was `2.50 g` and that of pure solvent `0.04 g`. The molecular weight of the solute is

Answer

`M=48`

Explanation

`(P-P_(s))/(P)=(0.087)/(2.175)= ((40)/(M))/((40)/(M)+(360)/(18))`
`rArr (2.175)/(0.087)=1+(360)/(18)xx(M)/(40)`
`rArr25=1+(M)/(2)`