If 36.0 g of glucose is present in 400 ml of solution, molarity of the solution is:

Answer

To find the molarity of the solution, we will follow these steps:

### Step 1: Write the formula for molarity
The formula for molarity (M) is given by:
\[ M = \frac{\text{Number of moles of solute}}{\text{Volume of solution in liters}} \]

### Step 2: Convert the volume from milliliters to liters
The volume of the solution is given as 400 ml. To convert this to liters:
\[ \text{Volume in liters} = \frac{400 \text{ ml}}{1000} = 0.4 \text{ L} \]

### Step 3: Calculate the number of moles of glucose
To find the number of moles, we use the formula:
\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \]
The given mass of glucose is 36 g, and the molar mass of glucose (C₆H₁₂O₆) is approximately 180 g/mol. Therefore:
\[ \text{Number of moles} = \frac{36 \text{ g}}{180 \text{ g/mol}} = 0.2 \text{ moles} \]

### Step 4: Substitute the values into the molarity formula
Now we can substitute the number of moles and the volume into the molarity formula:
\[ M = \frac{0.2 \text{ moles}}{0.4 \text{ L}} = 0.5 \text{ M} \]

### Final Answer
The molarity of the solution is:
\[ \text{Molarity} = 0.5 \text{ M} \]

---