When a liquid that is immiscible with water was steam distilled at `95.2^(@)C` at a total pressure of 748 torr, the distilled contained 1.25 g of the liquid per gram of water . The vapour pressure of water is 648 torr at `95.2^(@)C`, what is the molar mass of liquid?

Options

A. `7.975 g//"mol"`
B. `166 g//"mol"`
C. `145.8g//"mol"`
D. None of these

Answer

A, B, C, D

Explanation

For two immischible liquid ,
`P_(A)^(@)=P_("total")-P_(H_(2^(O)))^(@)=748-648rArr100`
`(W_(A))/(W_(B))=(P_(A)^(@)M_(A))/(P_(B)^(@)M_(B)) , M_(A)=(1.25)/(1)xx(648xx18)/(100)rArr145.8`