A parallel plate capacitor (without dielectric) is charged by a battery and kept connected to the battery. A dielectric salb of dielectric constant `'k'` is inserted between the plates fully occupying the space between the plates. The energy density of electric field between the plates will:

Options

A. increase `k^(2)` times
B. decrease `k^(2)` times
C. increas `k` times
D. decrease `k` times

Answer

C

Explanation

Energy density `=1/2kepsilon_(0)E^(2)`
Since the cell remains connected, V remains unchanged (and therefore E remains unchanged)
`implies` Energy density will increase k times.