Two identical balls `P` and `Q` moving in the `x-y` plane collide at the origin `(x=0,y=0)` of the coordinate system. Their velocity components just before the moment of impact were, for ball `P, v_(x)=6m//s, v_(y)=0,p` for ball `Q, v_(x)=-5m//s,v_(y)=2 m//s`
As a result of the collision, the ball `P` comes to rest. The velocity components of the ball `Q` just after collision will be:

Options

A. `v_(x)=0`
B. `v_(y)=2m//s`
C. `v_(y)=3m//s`
D. `v_(x)=1m//s`

Explanation

To solve the problem step-by-step, we will use the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

### Step 1: Identify the initial velocities of the balls
- For ball P:
- \( v_{Px} = 6 \, \text{m/s} \)
- \( v_{Py} = 0 \, \text{m/s} \)

- For ball Q:
...