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If `g(x)` is monotonically increasing and `f(x)` is monotonically decreasing for `x in R` and if `(gof) (x)` is defined for `x in R`, then prove that `(gof)(x)` will be monotonically decreasing function. Hence prove that` (gof) (x +1)leq (gof) (x-1). `

A

a. `g(f(ax+1))gtg(f(ax-1))` if `alt0`

B

b. `g(g(ax+1)gtg(g(ax-1))` if `alt0`

C

c. `g(f(ax+1)ltg(f(ax-1))` if `agt0`

D

d. `g(g(ax+1))gtg(g(ax-1))` if `agt0`

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