Home
Class 11
PHYSICS
A film of water is formed between two st...

A film of water is formed between two straight parallel wires each 10cm long and at a separation 0.5cm. Calculate the work required to increase 1 mm distance between them. Surface tension of water `=72xx10^(-3)N//m`

Text Solution

Verified by Experts

The correct Answer is:
`14.4 xx 10^(-6) J`
The process is shown in the figure. As we have to produce `2` film, so
`DeltaW = (2 DeltaA) T`
`= 2 [10 cm xx 0.6 cm - 10 cm xx 0.5 cm] xx 72 xx 10^(-3)(N)/(m)`
`= 2 xx (10 xx 10^(-2)m)(0.1 xx 10^(-2)m) xx 72 xx 10^(-3)(N)/(m)`
`= 1.44 xx 10^(-6) J`
Promotional Banner

Topper's Solved these Questions

  • SURFACE TENSION

    RESONANCE ENGLISH|Exercise Exercise- 1 PART - II|16 Videos

  • SURFACE TENSION

    RESONANCE ENGLISH|Exercise Exercise- 2 PART - I|5 Videos

  • SURFACE TENSION

    RESONANCE ENGLISH|Exercise Advanced Level Problems|17 Videos

  • STRING WAVES

    RESONANCE ENGLISH|Exercise Exercise|32 Videos

  • UNITS, DIMENSION & MEASUREMENT

    RESONANCE ENGLISH|Exercise Exercise|27 Videos

Similar Questions

Explore conceptually related problems

A film of water is formed between two straight parallel wires each 10 cm long and at a seperation of 0.5 cm . Calculate the work required to increase 1mm distance between the wires. Surface tension of water =72xx10^(-3)N//m .

A film of water is formed between two straight parallel wires each 10 cm long and at a seperation of 0.5 cm . Calculate the work required to increase 1mm distance between the wires. Surface tension of water =72xx10^(-3)N//m .

The length of needle floating on water is 2.5 cm. Calculate thhe added force required to pull the needle out of water (T=7.2xx10^(-2)N//m)

What should be the radius of a water drop so that the excess pressure inside it is 0.2 atm? Surface tension of water is 72 xx 10^(-3) N//m ?

Calculate the force required to separate the glass plates of area 10^(-2)m^(2) with a film of water 0.05 mm thickness between them (surface tension of water =70xx10^(-3)N//m) )

Calculate the pressue inside air bubble of diameter 0.2 mm situated just below the surface of water. Surface tension of water is 72 xx 10^(-3) Nm^(-1) .

Work done in splitting a drop of water of 1 mm radius into 10^(6) droplets is (Surface tension of water= 72xx10^(-3)J//m^(2) )

Two large glass plates are placed vertically and parallel to each other inside a tank of water with separation between the plates equal to 1 mm. Find the rise of water in the space between the plates. Surface tension of water =0.075Nm^-1 .

Two parallel wires each of length 10 cm are 0.5 cm apart. A film of water is formed between them. If surface tension of water is 0.072 N/m, then the work done in increasing the distance between the wires by 1 mm is:

The minimum force required to separate a light glass plate of perimeter 5m from a water surface is (Given surface tension of water = 70 xx 10^(-3) N/m)