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Assume that a drop of liquid evaporated ...

Assume that a drop of liquid evaporated by decreases in its suface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is `T`, density of liquid is `rho` and `L `is its latent heat of vaporization.
(a)`(rho L)/(T)` (b)`sqrt((T)/(rho L))` (c ) `(T)/(rhoL)` (d)`(2T)/(rho L)`.

A

`rhoL//T`

B

`sqrt(T//rhoL)`

C

`T//rhoL`

D

`2T//rhoL`

Text Solution

Verified by Experts

The correct Answer is:
D
When radius is decrease by dr
decreases in surface energy `=` Heat required for vaporisation
`(4pirdr) xx T xx 2 = 4pir^(2)drL rho`
`rArr = (2T)/(rhoL)`
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