There is soap bubble of radius 2.4xx10^(...

There is soap bubble of radius `2.4xx10^(-4)m` in air cylinder which is originally at the pressure of `10^(5)N//m^(2)` the air in the cylinder is now compressed isothermally unitl the radius of the bubble is halved. Calculate now the pressure of aire in the cylinder the surface tension of the soap film is `0.08Nm^(-1)`

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The correct Answer is:

`8.08 xx 10^(5)N//m^(2)`

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There is a soap bubble of radius 2.4xx10^(-4)m in air cylinder which is originally at a pressure of 10^(5)(N)/(m^(2)) . The air in the cylinder is now compressed isothermally until the radius of the bubble is halved. (the surface tension of the soap film is 0.08Nm^(-1)) . The pressure of air in the cylinder is found to be 8.08xx10^(n)(N)/(m^(2)) . What is the value of n?

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