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Three rods of uniform area of cross sect...

Three rods of uniform area of cross section `A =10^(-7)m^(2)` are arranged as shown in Fig. Find out the shift in point `B, C` and `D`.

Text Solution

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`DeltaL_(B)=DeltaL_(AB)=(FL)/(AY)=(MgL)/(AY)=(10xx10xx0.1)/(10^(-7)xx2.5xx10^(10))=4xx10^(-3)m=4mm`
`DeltaL_(C)=DeltaL_(B)+DeltaL_(BC)=4xx10^(-3)+(100xx0.2)/(10^(-7)xx4xx10^(10))=4xx10^(-3)+5xx10^(-3)=9mm`
`DeltaL_(D)=DeltaL_(C)+DeltaL_(CD)=9xx10^(-3)+(100xx0.15)/(10^(-7)xx1xx10^(10))=9xx10^(-3)+5xx10^(-3)=24mm`
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