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A rubber cube of side 5 cm has one side ...

A rubber cube of side `5 cm` has one side fixed while a tangential force equal to `1800 N` is applied to opposite face. Find the shearing strain and the lateral displacement of the strained face. Modulus of rigidity for rubber is `2.4 xx 10^(6) N//m^(2)`.

Text Solution

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`L = 5 xx 10^(-3)m rArr (F)/(A) = eta(x)/(L)`
strain `theta =m (F)/(Aeta) = (1800)/(25 xx 10^(-4) xx 2.4 xx 10^(6)) = (180)/(25 xx 24) = (3)/(10) = 0.3` radian
`(x)/(L) = 0.3 rArr x = 0.3 xx 5 xx 10^(-2) = 1.5 xx 10^(-2) m = 1.5 cm`
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