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A cubical block (of side 2m) of mass 20 ...

A cubical block (of side 2m) of mass 20 kg slides on inclined plane lubricated with the oil of viscosity ` eta = 10 ^(-1) ` poise with constant velocity of ` 10 m//sec. (g = 10 m//sec^ 2 ) `. Find out the thickness of layer of liquid in mm.

Text Solution

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`F = etaA (dv)/(dz) = mg sin theta (dv)/(dz) = (v)/(h)`
`20 xx 10 xx sin 30^(@) = eta xx 4 xx (10)/(h)`
`h = (40 xx 10^(-2))/(100) [eta = 10^(-1) poise = 10^(-2)N-sec-m^(-2)]`
`= 4 xx 10^(-3) m = 4 mm`
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