Home
Class 11
PHYSICS
A drop of water of radius 0.0015 mm is f...

A drop of water of radius `0.0015 mm` is falling in air. If the coefficient of viscosity of air is `1.8 xx 10^(-5)kg//ms`, what will be the terminal velocity of the drop? Density of water `= 1.0 xx 10^(3) kg//m^(3)` and `g = 9.8 N//kg`. Density of air can be neglected.

A

`3.25 xx 10^(-4) m//s`

B

`2.10 xx 10^(-4) m//s`

C

`1.5 xx 10^(-4) m//s`

D

`1.25 xx 10^(-4) m//s`

Text Solution

Verified by Experts

The correct Answer is:
C
`v = (2)/(9eta) r^(2).(rho_(0) - rho_(w))g`
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY AND VISCOCITY

    RESONANCE ENGLISH|Exercise Exercise- 2 PART - I|9 Videos

  • ELASTICITY AND VISCOCITY

    RESONANCE ENGLISH|Exercise Exercise- 2 PART - II|6 Videos

  • ELASTICITY AND VISCOCITY

    RESONANCE ENGLISH|Exercise Exercise- 1 PART - I|8 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE ENGLISH|Exercise dpp 92 illustration|2 Videos

  • ELECTROMAGNETIC INDUCTION

    RESONANCE ENGLISH|Exercise Exercise|43 Videos

Similar Questions

Explore conceptually related problems

A drop of water of radius 0.0015 mm is falling in air .If the cofficient of viscosity of air is 2.0 xx 10^(-5) kg m^(-1)s^(-1) ,the terminal velocity of the drop will be (The density of water = 10^(3) kg m^(-3) and g = 10 m s^(-2) )

An air bubble (radius 0.4 mm) rises up in water. If the coefficient of viscosity of water be 1xx10^(-3)kg//(m-s) , then determine the terminal speed of the bubble density of air is negligible

A drop of water of radius 10^(-5) m is falling through a medium whose density is 1.21 kg m^(-3) and coefficient of Viscosity 1.8xx10^(-4) poise. Find the terminal velocity of the drop.

A rain drop of radius 0.3 mm has a terminal velocity in air 1m/s. the viscosity of air is 18xx10^(-5) poise. The viscous force on it is-

A rain drop of radius 0.3 mm falls through air with a terminal viscosity of 1 m s^(-1) . The viscosity of air is 18 xx 10^(-5) poise. The viscous force on the rain drop is

A raindrop of radius 0.2 mm falls through air: If the viscosity of air is 18 xx 10^(-6) Pl, find the viscous drag acting on the drop when its speed is 1 m s^(-1) .

Compute the terminal velocity of a rain drop of radius 0.3 mm. Take coefficient of viscosity of air 1.83 X 10^(-5) poise and density of air = 1.3 kg m^(-3) Density of water - 10^(3) kg m^(-3) and take g= 9.8 ms^(-2)

Find the terminal velocity of a rain drop of radius 0.01 mm. The coefficient of viscosity of air is 1.8xx10^-5 N-sm^-2 and its density is 1.2kgm^-3 .Density of water =1000kgm^-3 . Take g=10ms^-2

Eight drops of water, each of radius 2mm are falling through air at a terminal velcity of 8cms^-1 . If they coalesce to form a single drop, then the terminal velocity of combined drop will be

Convert 1 mm of Hg into pascal. Take density of Hg=13.6xx10^(3)kg m^(-3) and g=9.8 ms^(-2) .