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Fundamental frequency of a organ pipe fi...

Fundamental frequency of a organ pipe filled with `N_(2)` is `1000 Hz`. Find the fundamental frequency if `N_(2)` is replaced by `H_(2)`.

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To solve the problem of finding the fundamental frequency of an organ pipe filled with hydrogen (H₂) after it was initially filled with nitrogen (N₂) at a frequency of 1000 Hz, we can follow these steps: ### Step 1: Understand the relationship between frequency and the properties of the gas The fundamental frequency (f) of an organ pipe is given by the formula: \[ f = \frac{V}{2L} \] where \( V \) is the velocity of sound in the gas and \( L \) is the length of the organ pipe. ### Step 2: Determine the velocity of sound in the gas The velocity of sound in a gas can be expressed as: \[ V = \sqrt{\frac{\gamma R T}{M}} \] where: - \( \gamma \) is the ratio of specific heats (constant for diatomic gases like N₂ and H₂), - \( R \) is the universal gas constant (constant), - \( T \) is the absolute temperature (assumed constant for both gases), - \( M \) is the molecular weight of the gas. ### Step 3: Establish the relationship between frequencies of different gases Since both nitrogen and hydrogen are diatomic gases, we can compare their frequencies. The fundamental frequency is inversely proportional to the square root of the molecular weight: \[ \frac{f_1}{f_2} = \sqrt{\frac{M_2}{M_1}} \] where: - \( f_1 \) is the frequency with nitrogen, - \( f_2 \) is the frequency with hydrogen, - \( M_1 \) is the molecular weight of nitrogen (N₂ = 28 g/mol), - \( M_2 \) is the molecular weight of hydrogen (H₂ = 2 g/mol). ### Step 4: Substitute the values into the equation Using the molecular weights: \[ \frac{f_1}{f_2} = \sqrt{\frac{2}{28}} = \sqrt{\frac{1}{14}} \] This can be rearranged to find \( f_2 \): \[ f_2 = f_1 \cdot \sqrt{14} \] ### Step 5: Calculate the new frequency Given that \( f_1 = 1000 \, \text{Hz} \): \[ f_2 = 1000 \cdot \sqrt{14} \] ### Step 6: Final calculation Calculating \( \sqrt{14} \approx 3.74 \): \[ f_2 \approx 1000 \cdot 3.74 \approx 3740 \, \text{Hz} \] ### Conclusion The fundamental frequency of the organ pipe when filled with hydrogen is approximately \( 3740 \, \text{Hz} \). ---

To solve the problem of finding the fundamental frequency of an organ pipe filled with hydrogen (H₂) after it was initially filled with nitrogen (N₂) at a frequency of 1000 Hz, we can follow these steps: ### Step 1: Understand the relationship between frequency and the properties of the gas The fundamental frequency (f) of an organ pipe is given by the formula: \[ f = \frac{V}{2L} \] where \( V \) is the velocity of sound in the gas and \( L \) is the length of the organ pipe. ...
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