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The distance between any two adjacent no...

The distance between any two adjacent nodes in a stationary wave is 15 cm. if the speed of the wave is 294 ms/, what is its frequency?

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The correct Answer is:
`(lambda)/(2) = 15cm` or `lambda = 30 cm = 0.3 m`,
`v = (c)/(lambda) = (3 xx 10^(8))/(0.3) = 10^(9) Hz`
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RESONANCE ENGLISH-SOUND WAVES-Board Level Exercise
  1. Give expressions of velocity of sound in solids and liquids.

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  2. you have learnt that a travelling wave in one dimension is represented...

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  3. (a) State and explain Newton's formula for the velocity of sound in th...

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  4. Use the formula v=sqrt((gammaP)/(rho)) to explain why the speed of sou...

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  5. Why the church bell has large surface area ?

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  6. Which characteristics of the sound helps you to identify your friend b...

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  7. How can we tell in a completely dark room that a particular soun is pr...

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  8. The identical sound waves pass through a medium at a point at the diff...

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  9. Why is it not possible to have interference between the waves produced...

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  10. Discuss the conditions for having (a) interference , (b) maxima and ...

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  11. The sound produced in a big hall repeats itself. Why ?

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  12. Why a stationary wave is called so ?

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  13. The distance between any two adjacent nodes in a stationary wave is 15...

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  14. The transverse displacement of a string (clamped at its ends) is given...

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  15. The transverse displacement of a string clamped at its both ends is gi...

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  16. Given below are some functions of x and t to represent the displacemen...

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  17. A metre-long tube open at one end, with a movable piston at the other ...

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  18. Why no beats can be heard if the frequencies of the two interfering wa...

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  19. (a) Explain the phenomesnon of beats ? (b) Compare and contreast it ...

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  20. Briefly enumerate the uses of beats.

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