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The equation of a longitudinal standing ...

The equation of a longitudinal standing wave due to superposition of the progressive waves producted by two sources of sound is `s = -20 sin 10 pix sin 100 pit` where `s` is the displacement from mean position measured in `mm, x` is in meters and is in seconds. The specific gravity of the medium is `10^(-3)`. Density of water `= 10^(3)kg//m^(3)`. Find :
(a) Wavelength, frequency and velocity of the progressive waves.
(b) Bulk modulus of the medium and the pressure amplitude.
(c) Minimum distance between pressure antinode and a displacement anotinode.
(d) Intensity at the displacement nodes.

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To solve the given problem step by step, we will break it down into the four parts as specified in the question. ### Given: The equation of the standing wave is: \[ s = -20 \sin(10 \pi x) \sin(100 \pi t) \] Where: - \( s \) is the displacement in mm, - \( x \) is in meters, - \( t \) is in seconds. The specific gravity of the medium is \( 10^{-3} \) and the density of water is \( 10^{3} \, \text{kg/m}^3 \). ### (a) Wavelength, Frequency, and Velocity of the Progressive Waves 1. **Frequency Calculation:** The angular frequency \( \omega \) can be identified from the term \( \sin(100 \pi t) \). \[ \omega = 100 \pi \] The frequency \( f \) is given by: \[ f = \frac{\omega}{2\pi} = \frac{100 \pi}{2\pi} = 50 \, \text{Hz} \] 2. **Wavelength Calculation:** The wave number \( k \) can be identified from the term \( \sin(10 \pi x) \). \[ k = 10 \pi \] The wavelength \( \lambda \) is given by: \[ \lambda = \frac{2\pi}{k} = \frac{2\pi}{10\pi} = \frac{1}{5} \, \text{m} = 20 \, \text{cm} \] 3. **Velocity Calculation:** The velocity \( v \) of the wave is given by: \[ v = f \cdot \lambda = 50 \cdot \frac{1}{5} = 10 \, \text{m/s} \] ### (b) Bulk Modulus of the Medium and Pressure Amplitude 1. **Bulk Modulus Calculation:** The bulk modulus \( B \) is given by: \[ B = \rho v^2 \] The density \( \rho \) of the medium can be calculated using specific gravity: \[ \rho = 10^{-3} \cdot 10^{3} = 1 \, \text{kg/m}^3 \] Now substituting the values: \[ B = 1 \cdot (10)^2 = 100 \, \text{N/m}^2 \] 2. **Pressure Amplitude Calculation:** The pressure amplitude \( P_0 \) is given by: \[ P_0 = B \cdot k \cdot S_0 \] Where \( S_0 = 20 \, \text{mm} = 20 \times 10^{-3} \, \text{m} \). \[ P_0 = 100 \cdot 10\pi \cdot (20 \times 10^{-3}) = 25 \, \text{N/m}^2 \] ### (c) Minimum Distance Between Pressure Antinode and Displacement Antinode The minimum distance between a pressure antinode and a displacement antinode is given by: \[ \text{Distance} = \frac{\lambda}{4} = \frac{20 \, \text{cm}}{4} = 5 \, \text{cm} \] ### (d) Intensity at the Displacement Nodes The intensity \( I \) at the displacement nodes is given by: \[ I = \frac{P_0^2}{2 \rho v} \] Substituting the values: \[ I = \frac{(25)^2}{2 \cdot 1 \cdot 10} = \frac{625}{20} = 31.25 \, \text{W/m}^2 \] ### Summary of Results: - (a) Wavelength = 20 cm, Frequency = 50 Hz, Velocity = 10 m/s - (b) Bulk Modulus = 100 N/m², Pressure Amplitude = 25 N/m² - (c) Minimum Distance = 5 cm - (d) Intensity = 31.25 W/m²

To solve the given problem step by step, we will break it down into the four parts as specified in the question. ### Given: The equation of the standing wave is: \[ s = -20 \sin(10 \pi x) \sin(100 \pi t) \] Where: - \( s \) is the displacement in mm, - \( x \) is in meters, ...
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