Two indentical piano wires, kept under the same tension T have a fundamental frequency of 600Hz. The fractional increase in the tension of one of the wires which will lead to occurrence of 6 beats/s when both the wires oscillate together would be :

Answer

`2%`

Explanation

`f = (1)/(lambda) sqrt((T)/(mu))`
`lnf = -lnlambda + (1)/(2)lnT - (1)/(2)ln mu`
`(1)/(f) (df)/(dT) = 0 + (1)/(2) (1)/(T) - 0`
`(df)/(f) = (1)/(2)(dT)/(T)`
`(dT)/(T) = (2df)/(f) = (2 xx 6)/(600) = (2)/(100)`
`%` change `= (2)/(100) xx 100 = 2%`