If `lambda_(1), lamda_(2)and lamda_(3)` are the wavelengths of the wave giving resonance with the fundamental, first and second overtones respectively of a closed organ pipe Then the ratio of wavelength `lambda_(1), lamda_(2)and lamda_(3)` is

Options

A. `1 : 2 : 3`
B. `1 : 3 : 5`
C. `1 : 1//2 : 1//3`
D. `1 : 1//3 : 1//5`

Answer

C

Explanation

`n_(1) : n_(2) : n_(3) = 1 : 2 : 3`
`(V)/(lambda_(1)) : (V)/(lambda_(2)) : (V)/(lambda_(3)) = 1 : 2 : 3`
`lambda_(1) : lambda_(2) : lambda_(3) = 1 : (1)/(2) : (1)/(3)`