`X(C_(4)H_(9)Br) underset(Delta) overset(alc.KOH)to Yoverset(Br_(2)//"CC"l_(4)) rarrZ underset(Delta) overset(NaNH_(2)(2eq.))to W underset(("Tollen's reagent")) overset(AgNO_(3)+NH_(4)OH)to`white ppt
Reductive ozonolysis of `Y` yields

Options

A. `CH_(3)CH_(2)CHO` and `HCHO`
B. `2` moles of `CH_(3)CHO`
C. `CH_(3)CO CH_(3)` and `HCHO`
D. `CH_(3)CH_(2)COOH` and `HCOOH`

Explanation

To solve the given question step by step, we will analyze each part of the reaction sequence provided.

### Step 1: Identify Compound X
The compound X is given as C₄H₉Br. This indicates that it is a brominated alkane. The presence of bromine suggests that it can undergo elimination reactions.

### Step 2: Reaction of X with Alcoholic KOH
When X reacts with alcoholic KOH under heat, it will undergo an elimination reaction (dehydrohalogenation) to form an alkene (Y). The structure of Y can be predicted as follows:
- Since X has 4 carbons and one bromine, we can assume a linear structure.
- The elimination will likely produce a double bond.

Assuming the structure of X is 1-bromobutane (CH₃CH₂CH₂CH₂Br), the elimination reaction will yield:
- **Y = But-1-ene (CH₃CH₂CH=CH₂)**

### Step 3: Reaction of Y with Br₂ in CCl₄
Next, Y (But-1-ene) reacts with Br₂ in CCl₄. This reaction will add bromine across the double bond, resulting in a dibrominated compound (Z):
- **Z = 1,2-Dibromobutane (CH₃CHBrCHBrCH₃)**

### Step 4: Reaction of Z with NaNH₂
Z then reacts with 2 equivalents of NaNH₂, which will facilitate a double elimination reaction to form an alkyne (W):
- The elimination will remove the two bromine atoms and two hydrogen atoms, resulting in:
- **W = Butyne (CH₃C≡CCH₃)**

### Step 5: Reaction of W with Tollen's Reagent
W (Butyne) reacts with Tollen's reagent (AgNO₃ + NH₄OH). Tollen's reagent is used to test for aldehydes, and since butyne can be oxidized to form an aldehyde, we can expect:
- **White precipitate of silver (Ag) indicates the presence of an aldehyde.**

### Step 6: Reductive Ozonolysis of Y
Finally, we need to determine the products of the reductive ozonolysis of Y (But-1-ene). The ozonolysis of alkenes typically results in the formation of carbonyl compounds (aldehydes or ketones). For But-1-ene:
- The ozonolysis will cleave the double bond and add oxygen, resulting in:
- **Products: CH₃CH₂CHO (butanal) and HCHO (formaldehyde)**

### Summary of Structures
- **X = 1-bromobutane (CH₃CH₂CH₂CH₂Br)**
- **Y = But-1-ene (CH₃CH₂CH=CH₂)**
- **Z = 1,2-Dibromobutane (CH₃CHBrCHBrCH₃)**
- **W = Butyne (CH₃C≡CCH₃)**
- **Reductive ozonolysis of Y yields: Butanal (CH₃CH₂CHO) and Formaldehyde (HCHO)**