`X(C_(4)H_(9)Br) underset(Delta) overset(alc.KOH)to Yoverset(Br_(2)//"CC"l_(4)) rarrZ underset(Delta) overset(NaNH_(2)(2eq.))to W underset(("Tollen's reagent")) overset(AgNO_(3)+NH_(4)OH)to`white ppt
Which of the following statement(s) is//are incorrect?

Options

A. `Y` and `W` are chain isomers
B. `Y` and `W` are functional isomers
C. `W` can be converted into `Y` with `H_(2)//Pt`
D. `W` can be converted into `Y` with Lindlar catalyst

Explanation

To solve the given question step by step, let's analyze the reactions and compounds involved:

1. **Identify the starting compound (X)**:
- The molecular formula of compound X is C₄H₉Br. This indicates it is a bromoalkane.

2. **Reaction of X with alcoholic KOH**:
- When X reacts with alcoholic KOH under heat, it undergoes an elimination reaction (dehydrohalogenation) to form an alkene (Y).
- The elimination will typically remove the bromine and a hydrogen atom from adjacent carbon atoms, resulting in a double bond.

3. **Formation of compound Y**:
- The structure of Y will be an alkene. Since we are starting from a bromoalkane, we can assume Y is a butene (for example, 1-butene or 2-butene).

4. **Reaction of Y with Br₂/CCl₄**:
- The alkene Y will react with bromine in carbon tetrachloride (CCl₄), resulting in the addition of bromine across the double bond, forming a dibromide (Z).

5. **Formation of compound Z**:
- The structure of Z will have two bromine atoms added to the former double bond positions of Y.

6. **Reaction of Z with NaNH₂ (2 eq.)**:
- Sodium amide (NaNH₂) will induce a double elimination reaction on Z, resulting in the formation of an alkyne (W).
- This means that two bromine atoms will be removed, along with two hydrogen atoms, resulting in a triple bond.

7. **Formation of compound W**:
- The structure of W will be a terminal alkyne, which can be represented as RC≡C-H, where R is the remaining carbon chain.

8. **Reaction of W with Tollen's reagent**:
- Tollen's reagent (AgNO₃ + NH₄OH) is used to test for aldehydes or terminal alkynes. In this case, W (the terminal alkyne) will give a positive test, resulting in a white precipitate of silver.

9. **Identifying incorrect statements**:
- The question asks which statements are incorrect regarding the compounds formed and their properties.
- From the analysis:
- Statement 1: "Y and W are chain isomers." This is incorrect because Y (alkene) and W (alkyne) are functional isomers, not chain isomers.
- Statement 2: "W can be converted into Y with H₂/Pd." This is correct because hydrogenation can convert alkynes to alkenes.
- Statement 3: "W can be converted into Y with Lindlar reagent." This is also correct, as Lindlar catalyst selectively hydrogenates alkynes to cis-alkenes.

### Summary of the solution:
- The incorrect statement is the first one: "Y and W are chain isomers." They are functional isomers, not chain isomers.