State true or false :
The geometry of phosphorus in `H_(3)PO_(2),H_(3)PO_(3)` and `H_(3)PO_(4)` is tetrahedral

Explanation

To determine whether the statement "The geometry of phosphorus in H₃PO₂, H₃PO₃, and H₃PO₄ is tetrahedral" is true or false, we can analyze the molecular structures of each compound.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We are looking at three compounds: H₃PO₂ (phosphorous acid), H₃PO₃ (phosphorous acid), and H₃PO₄ (phosphoric acid).

2. **Draw the Lewis Structures**:
- **H₃PO₂**:
- Phosphorus (P) is the central atom. It forms a double bond with one oxygen (O) and is bonded to two hydrogen (H) atoms and one hydroxyl group (OH).
- Structure: O=P(OH)(H)(H)
- **H₃PO₃**:
- Phosphorus is again the central atom. It forms a double bond with one oxygen and is bonded to one hydrogen atom and two hydroxyl groups.
- Structure: O=P(OH)(OH)(H)
- **H₃PO₄**:
- Phosphorus is the central atom. It forms a double bond with one oxygen and is bonded to three hydroxyl groups.
- Structure: O=P(OH)(OH)(OH)

3. **Determine Hybridization**:
- In all three cases, phosphorus is bonded to four groups (either H or OH and one double-bonded O).
- This indicates that phosphorus is sp³ hybridized.

4. **Determine Geometry**:
- The geometry associated with sp³ hybridization is tetrahedral.
- Therefore, the geometry of phosphorus in H₃PO₂, H₃PO₃, and H₃PO₄ is tetrahedral.

5. **Conclusion**:
- Since all three compounds have phosphorus with tetrahedral geometry, the statement is **True**.

### Final Answer:
The statement is **True**.