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0.001 moles of a compound is present in ...

0.001 moles of a compound is present in 100 mL of its solution. The concentration of solution is:

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To find the concentration of the solution in terms of molarity, we can follow these steps: ### Step 1: Identify the given data - Number of moles of the compound (n) = 0.001 moles - Volume of the solution (V) = 100 mL ### Step 2: Convert the volume from mL to L To convert milliliters to liters, we use the conversion factor: \[ 1 \text{ L} = 1000 \text{ mL} \] Thus, \[ V = 100 \text{ mL} = \frac{100}{1000} \text{ L} = 0.1 \text{ L} \] ### Step 3: Use the formula for molarity Molarity (M) is defined as the number of moles of solute divided by the volume of solution in liters: \[ M = \frac{n}{V} \] Where: - \( n \) = number of moles of solute - \( V \) = volume of solution in liters ### Step 4: Substitute the values into the formula Substituting the values we have: \[ M = \frac{0.001 \text{ moles}}{0.1 \text{ L}} \] ### Step 5: Calculate the molarity Now, performing the calculation: \[ M = \frac{0.001}{0.1} = 0.01 \text{ M} \] ### Conclusion The concentration of the solution is **0.01 M** (molar). ---

To find the concentration of the solution in terms of molarity, we can follow these steps: ### Step 1: Identify the given data - Number of moles of the compound (n) = 0.001 moles - Volume of the solution (V) = 100 mL ### Step 2: Convert the volume from mL to L To convert milliliters to liters, we use the conversion factor: ...
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