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In an experiment, 50 mL of 0.1 M solutio...

In an experiment, 50 mL of 0.1 M solution off a metallic salt `M(NO_(3))` reacted exactly with 25 mL of 0.1 M solution of `NaSO_(3)` in the reaction `SO_(3)^(2-)` is oxidized to `SO_(4)^(2-)`. If in the original salt oxidation number of the metal was 3, what would be the new oxidation number of metal?

Text Solution

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The correct Answer is:
2
meq of `Na_(2)SO_(3)=` meq of salt
`25xx0.1xx2=50xx0.1xxn` factor.
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