When `NaBH_(4)` is dissolved in water

Options

A. `Na^(+)` and `BH_(4)^(-)` ions are formed which are stable
B. It decomposes with evolution of `H_(2)`
C. `BH_(4)^(-)` is formed initially decomposed to give `OH^(ɵ)` ion which prevents further decomposition.
D. `NaOH` and `H_(3)BO_(3)` is formed

Explanation

To solve the question "When NaBH₄ is dissolved in water, what happens?", we can break down the process step by step.

### Step-by-Step Solution:

1. **Identify the Compound**:
- Sodium borohydride is represented as NaBH₄.

2. **Dissolution in Water**:
- When NaBH₄ is dissolved in water, it dissociates into its ions:
\[ \text{NaBH}_4 \rightarrow \text{Na}^+ + \text{BH}_4^- \]
- Here, Na⁺ is the sodium ion and BH₄⁻ is the borohydride ion.

3. **Reaction with Water**:
- The borohydride ion (BH₄⁻) reacts with water (H₂O). The water dissociates into H⁺ and OH⁻ ions:
\[ \text{BH}_4^- + \text{H}_2O \rightarrow \text{B(OH)}_4^- + \text{H}_2 \]
- This reaction produces hydrogen gas (H₂) as a byproduct.

4. **Formation of Sodium Hydroxide**:
- The sodium ion (Na⁺) from the dissociation of NaBH₄ reacts with the hydroxide ion (OH⁻) produced from water:
\[ \text{Na}^+ + \text{OH}^- \rightarrow \text{NaOH} \]
- This results in the formation of sodium hydroxide (NaOH).

5. **Summary of Products**:
- The main products of this reaction are sodium hydroxide (NaOH) and hydrogen gas (H₂).
- The reaction can be summarized as:
\[ \text{NaBH}_4 + \text{H}_2O \rightarrow \text{NaOH} + \text{H}_2 + \text{B(OH)}_4^- \]

6. **Stability of Ions**:
- The ions formed (Na⁺, OH⁻, and BH₄⁻) are not stable in the sense that they can further react, but the presence of NaOH helps to prevent further decomposition of NaBH₄.

### Conclusion:
- When NaBH₄ is dissolved in water, it dissociates into Na⁺ and BH₄⁻, reacts with water to produce NaOH and H₂ gas, and the BH₄⁻ ion initially formed can further react but is stabilized by the presence of NaOH.