If 180 g of glucose is present in 400 ml of solution, molarity of the solution is:

Explanation

To find the molarity of the glucose solution, we can follow these steps:

### Step 1: Convert the volume of the solution from milliliters to liters.
Given:
- Volume of the solution = 400 ml

To convert milliliters to liters:
\[ \text{Volume in liters} = \frac{\text{Volume in ml}}{1000} = \frac{400 \, \text{ml}}{1000} = 0.4 \, \text{liters} \]

### Step 2: Calculate the number of moles of glucose.
Given:
- Mass of glucose = 180 g
- Molecular mass of glucose (C₆H₁₂O₆) = 180 g/mol

To find the number of moles:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} = \frac{180 \, \text{g}}{180 \, \text{g/mol}} = 1 \, \text{mol} \]

### Step 3: Calculate the molarity of the solution.
The formula for molarity (M) is:
\[ \text{Molarity (M)} = \frac{\text{Number of moles of solute}}{\text{Volume of solution in liters}} \]
Substituting the values we have:
\[ \text{Molarity} = \frac{1 \, \text{mol}}{0.4 \, \text{liters}} = 2.5 \, \text{M} \]

### Conclusion:
The molarity of the glucose solution is **2.5 M**.

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