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henry's law constant for CO(2) in water ...

henry's law constant for `CO_(2)` in water is `2.5xx10^(8)` Pa at `298K` calcualte mmole of `CO_(2)` dissolbed in 144 g water at 2.5 atm pressure at 298K. [take 1 atm `=10^(6)(N)/(m^(2))` or Pa]

A

`12`

B

`8`

C

`4`

D

`2`

Text Solution

Verified by Experts

The correct Answer is:
B
`P_(CO_(2))=k_(H).X_(CO_(2))=K_(H)xx(n_(CO_(2)))/(n_(CO_(2))+N_(water))`
`=K_(H) (n_(CO_(2)))/(n_(water))`
`2.5xx10^(5)=2.5xx10^(8)xx(n_(CO_(2)))/(144//18)`
`n_(CO_(2))=8xx10^(-3)`
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