Find the total number of acidic radical which prodce with dil `HCl`
`SO_(4)^(2-),I^(-),NO_(2)^(-),SO_(3)^(2-),HCO_(3)^(-)`

Explanation

To solve the problem of finding the total number of acidic radicals that produce with dilute HCl from the given anionic species, we will analyze each species one by one.

### Step-by-Step Solution:

1. **Understanding Acidic Radicals:**
Acidic radicals are the negative ions that can combine with hydrogen ions (H⁺) to form acids. In this case, we are using dilute HCl, which dissociates into H⁺ and Cl⁻.

2. **List of Given Anionic Species:**
The anionic species provided are:
- SO₄²⁻
- I⁻
- NO₂⁻
- SO₃²⁻
- HCO₃⁻

3. **Analyzing Each Anionic Species:**
- **SO₄²⁻ (Sulfate):**
When SO₄²⁻ reacts with H⁺, it forms HSO₄⁻ (hydrogen sulfate). However, HSO₄⁻ can donate a proton (H⁺) and act as a base, so it is not considered an acidic radical.
- **Conclusion:** Not an acidic radical.

- **I⁻ (Iodide):**
When I⁻ reacts with H⁺, it forms HI (hydroiodic acid), which is a strong acid.
- **Conclusion:** This is an acidic radical.

- **NO₂⁻ (Nitrite):**
When NO₂⁻ reacts with H⁺, it forms HNO₂ (nitrous acid), which is a weak acid.
- **Conclusion:** This is an acidic radical.

- **SO₃²⁻ (Sulfite):**
When SO₃²⁻ reacts with H⁺, it forms HSO₃⁻ (hydrogen sulfite). Similar to sulfate, HSO₃⁻ can donate a proton and is not considered an acidic radical.
- **Conclusion:** Not an acidic radical.

- **HCO₃⁻ (Bicarbonate):**
When HCO₃⁻ reacts with H⁺, it forms H₂CO₃ (carbonic acid), which is an acid.
- **Conclusion:** This is an acidic radical.

4. **Counting the Acidic Radicals:**
From our analysis:
- I⁻: Acidic radical
- NO₂⁻: Acidic radical
- HCO₃⁻: Acidic radical
- SO₄²⁻: Not an acidic radical
- SO₃²⁻: Not an acidic radical

Therefore, the total number of acidic radicals is **3**.

### Final Answer:
The total number of acidic radicals that produce with dilute HCl from the given species is **3**.