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For the cell (at 298K) Ag(s) | AgCl(s)...

For the cell (at 298K)
`Ag(s) | AgCl(s) | Cl^(-)(aq)|| AgNO_(3)(aq) | Ag(s)`
Which of the following is correct?

A

The cell emf will be zero when `[(Ag^(+))]` in anodic compartment =`[Ag^(+)]` in cathodic compartment

B

The amount of AgCl(s) precipitate in anodic compartment will decrease with the working of the cell

C

The concentration of `[Ag^(+)]`=constant, in anodic compartment during working of cell

D

`E_(cell)=E_(Ag^(+)|Ag)^(0)-E_(Cl^(-)|AgCl|Ag)^(0)-0.059/1"log"1/[Cl^(-)]_(a)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the electrochemical cell given, we will analyze the cell notation and apply the Nernst equation to determine the correctness of the statements provided. ### Step-by-Step Solution: 1. **Identify the Components of the Cell:** The cell notation is given as: \[ \text{Ag(s)} | \text{AgCl(s)} | \text{Cl}^-(\text{aq}) || \text{AgNO}_3(\text{aq}) | \text{Ag(s)} \] This indicates that we have a silver/silver chloride electrode on the left and a silver electrode in a silver nitrate solution on the right. 2. **Determine the Half-Reactions:** The half-reactions for the cell can be written as: - Anode (oxidation): \[ \text{AgCl(s)} + \text{e}^- \rightarrow \text{Ag(s)} + \text{Cl}^-(\text{aq}) \] - Cathode (reduction): \[ \text{Ag}^+(\text{aq}) + \text{e}^- \rightarrow \text{Ag(s)} \] 3. **Write the Nernst Equation:** The Nernst equation for the cell can be expressed as: \[ E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{0.0591}{n} \log \left( \frac{[\text{Ag}^+]_{\text{anode}}}{[\text{Ag}^+]_{\text{cathode}}} \right) \] Here, \( n = 1 \) (one electron is transferred). 4. **Evaluate the Condition for EMF = 0:** The EMF of the cell will be zero when the concentrations of silver ions in both compartments are equal: \[ [\text{Ag}^+]_{\text{anode}} = [\text{Ag}^+]_{\text{cathode}} \] In this case, the log term becomes log(1) = 0, leading to: \[ E_{\text{cell}} = E^\circ_{\text{cell}} - 0 = E^\circ_{\text{cell}} \] Therefore, the first statement is correct. 5. **Analyze the Other Statements:** - **Statement 2:** "The amount of AgCl precipitate in the anodic compartment will decrease with the working of the cell." - This statement is incorrect because as the cell operates, AgCl will dissolve, leading to a decrease in AgCl precipitate. - **Statement 3:** "Concentration of Ag^+ is constant in the anodic compartment during working of the cell." - This statement is incorrect because the concentration of Ag^+ will change as the cell operates. - **Statement 4:** The last statement is also incorrect based on the analysis of the Nernst equation. 6. **Conclusion:** The only correct statement is the first one. Therefore, the answer is: \[ \text{Correct Answer: Option 1} \]

To solve the question regarding the electrochemical cell given, we will analyze the cell notation and apply the Nernst equation to determine the correctness of the statements provided. ### Step-by-Step Solution: 1. **Identify the Components of the Cell:** The cell notation is given as: \[ \text{Ag(s)} | \text{AgCl(s)} | \text{Cl}^-(\text{aq}) || \text{AgNO}_3(\text{aq}) | \text{Ag(s)} ...
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