The E(Cell)^(@)=1.18V for Zn(s)||Zn^(+2)...

The `E_(Cell)^(@)=1.18V` for `Zn(s)||Zn^(+2)(1M)||Cu^(+2)(1M)|Cu(s)`. The value of `x` if when excess granulated zinc is added to `1M Cu^(+2)` solution the `[Cu^(+2)]_(eq)` becomes `10^(-x)M` is `(T=298 K ,(2.303RT)/(F)=0.059)`

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The correct Answer is:

`E_(cell)=E_(cell)^@-0.0590/2 "log"([Zn^(+2)])/([Cu^(+2)])`
At equilibrium `E_(cell)=0`
`0.0590/2 "log" 1/10^(-x)=1.18`
x=40

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