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The EMF of a cell corresponding to the r...

The EMF of a cell corresponding to the reaction : `Zn_((s)) + 2H_((aq))^(+) toZn^(2+) (0.1 M) + H_(2(g)) ` ( 1 atm ) is 0.28 volt at `15^@C`.
The pH of the solution at the hydrogen electrode is (Given : `E_(Zn^(2+)//Zn)^@`=-0.76 volt , `E_(H^+ // H_2)^@`= 0 volt )

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Verified by Experts

The correct Answer is:
9
`E_(cell)^@=0.76` volt
Applying nernst equation
`E_(cell)=E_(cell)^@(-0.0591)/2"log"([Zn^(2+)][P_(H_2)])/([H^+]^2), " " 0.26=0.76(-0.0591)/2"log"((0.1)(1))/([H^+]^2)`
log `0.1/([H^+]^2)=(2xx0.50)0.0591`
or log 0.1-log `[H^+]^2=17` or 2pH=17-log 0.1
pH=`18/2=9`
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