`{:("Column-I","Column-II"),((A)NH_4Cl "in water", (p)"Neutral solution which does not undergo hydrolysis"),((B)CH_3COONa "in water" ,(q)"Cationic hydrolysis"),((C )NH_4CN "in water",(r)"Anionic hydrolysis"),((D)"NaCl in water",(s)"Both Cation and Anionic hydrolysis"):}`

Explanation

To solve the problem of matching salts in water with their respective types of hydrolysis, we will analyze each salt and determine the nature of the ions produced when they dissolve in water.

### Step-by-Step Solution:

1. **Identify the Ions in NH4Cl:**
- NH4Cl dissociates into NH4+ (ammonium ion) and Cl- (chloride ion).
- NH4+ is derived from a weak base (NH4OH) and Cl- from a strong acid (HCl).
- Since NH4+ is a cation from a weak base, it will undergo hydrolysis, while Cl- will not.

**Match:** A (NH4Cl) → Q (Cationic hydrolysis)

2. **Identify the Ions in CH3COONa:**
- CH3COONa dissociates into CH3COO- (acetate ion) and Na+ (sodium ion).
- CH3COO- comes from a weak acid (CH3COOH) and Na+ from a strong base (NaOH).
- CH3COO- being an anion from a weak acid will undergo hydrolysis.

**Match:** B (CH3COONa) → R (Anionic hydrolysis)

3. **Identify the Ions in NH4CN:**
- NH4CN dissociates into NH4+ (ammonium ion) and CN- (cyanide ion).
- Both NH4+ and CN- are derived from weak acid (HCN) and weak base (NH4OH).
- Since both ions can undergo hydrolysis, NH4CN will show both cationic and anionic hydrolysis.

**Match:** C (NH4CN) → S (Both Cation and Anionic hydrolysis)

4. **Identify the Ions in NaCl:**
- NaCl dissociates into Na+ (sodium ion) and Cl- (chloride ion).
- Both Na+ and Cl- come from a strong base (NaOH) and a strong acid (HCl), respectively.
- Neither ion will undergo hydrolysis, resulting in a neutral solution.

**Match:** D (NaCl) → P (Neutral solution which does not undergo hydrolysis)

### Final Matches:
- A → Q (Cationic hydrolysis)
- B → R (Anionic hydrolysis)
- C → S (Both Cation and Anionic hydrolysis)
- D → P (Neutral solution which does not undergo hydrolysis)

### Summary of Matches:
- A: NH4Cl → Q
- B: CH3COONa → R
- C: NH4CN → S
- D: NaCl → P