Home
Class 12
CHEMISTRY
For a solution of 0.89 g of mercurous c...

For a solution of 0.89 g of mercurous chloride in 50 g of `HgCl_(2)(l)` the freezing point depression id `1.24^(@)`C. `K_(f)` for `HgCl_(2)` is 34.3 . What is the state of mercurous chloride in `HgCL_(2)`? (Hg-200, Cl-35.5).

A

as `Hg_2Cl_2` molecules

B

as `HgCl` molecules

C

as `Hg^+` and `Cl^(-)` ions

D

as `Hg_2^2+ and Cl^(-)` ions

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the state of mercurous chloride (Hg2Cl2) in a solution of mercurous chloride in mercuric chloride (HgCl2) based on the freezing point depression observed. ### Step-by-Step Solution: 1. **Identify Given Data:** - Mass of mercurous chloride (Hg2Cl2) = 0.89 g - Mass of mercuric chloride (HgCl2) = 50 g - Freezing point depression (ΔTf) = 1.24 °C - Cryoscopic constant (Kf) for HgCl2 = 34.3 °C kg/mol - Molar mass of Hg = 200 g/mol - Molar mass of Cl = 35.5 g/mol 2. **Calculate the Molar Mass of Mercurous Chloride (Hg2Cl2):** \[ \text{Molar mass of Hg2Cl2} = 2 \times 200 + 2 \times 35.5 = 400 + 71 = 471 \text{ g/mol} \] 3. **Calculate the Number of Moles of Mercurous Chloride:** \[ \text{Number of moles of Hg2Cl2} = \frac{\text{mass}}{\text{molar mass}} = \frac{0.89 \text{ g}}{471 \text{ g/mol}} \approx 0.00189 \text{ mol} \] 4. **Convert the Mass of Solvent (HgCl2) to kg:** \[ \text{Mass of HgCl2 in kg} = \frac{50 \text{ g}}{1000} = 0.050 \text{ kg} \] 5. **Calculate the Molality (m) of the Solution:** \[ m = \frac{\text{number of moles of solute}}{\text{mass of solvent in kg}} = \frac{0.00189 \text{ mol}}{0.050 \text{ kg}} \approx 0.0378 \text{ mol/kg} \] 6. **Use the Freezing Point Depression Formula:** \[ \Delta T_f = i \cdot K_f \cdot m \] Rearranging for \(i\): \[ i = \frac{\Delta T_f}{K_f \cdot m} = \frac{1.24}{34.3 \cdot 0.0378} \] 7. **Calculate \(i\):** \[ i \approx \frac{1.24}{1.29534} \approx 0.958 \] 8. **Interpret the Value of \(i\):** Since \(i \approx 1\), this indicates that mercurous chloride does not dissociate or associate in the solution, meaning it remains as Hg2Cl2. ### Conclusion: The state of mercurous chloride in HgCl2 is that it remains as the intact molecule Hg2Cl2.

To solve the problem, we need to determine the state of mercurous chloride (Hg2Cl2) in a solution of mercurous chloride in mercuric chloride (HgCl2) based on the freezing point depression observed. ### Step-by-Step Solution: 1. **Identify Given Data:** - Mass of mercurous chloride (Hg2Cl2) = 0.89 g - Mass of mercuric chloride (HgCl2) = 50 g - Freezing point depression (ΔTf) = 1.24 °C ...
Promotional Banner

Topper's Solved these Questions

  • QUALITATIVE ANALYSIS PART 1

    RESONANCE ENGLISH|Exercise A.L.P|39 Videos
  • SOLID STATE

    RESONANCE ENGLISH|Exercise PHYSICAL CHEMITRY (SOLID STATE)|45 Videos

Similar Questions

Explore conceptually related problems

0.1 mole of sugar is dissolved in 250 g of water. The freezing point of the solution is [K_(f) "for" H_(2)O = 1.86^(@)C "molal"^(-1)]

2.56 g of suphur in 100 g of CS_(2) has depression in freezing point of 0.010^(@)C , K_(f)=0.1^(@)C (molal)^(-1) . Hence atomicity of sulphur in the solution is

2.56g of sulfur in 100 g of CS_(2) of has depression in freez point of 0.01^(@)C.K_(f)=0.1^(@) mol al^(-1) . Hence, he atomicity of sulfur is CS_(2) is

2.56g of sulfur in 100 g of CS_(2) of has depression in freez point of 0.01^(@)C.K_(f)=0.1^(@) mol al^(-1) . Hence, he atomicity of sulfur is CS_(2) is

45 g of ethylene glycol (C_(2) H_(6)O_(2)) is mixed with 600 g of water. The freezing point of the solution is (K_(f) for water is 1.86 K kg mol^(-1) )

When 20 g of naphthoic acid (C_(11)H_(8)O_(2)) is dissolved in 50 g of benzene (K_(f)=1.72 K kg mol^(-1)) , a freezing point depression of 2 K is observed. The Van't Hoff factor (i) is

The freezing point of a solution of 2.40 g of biphenyl ( C_(12)H_(10) ) in 75.0 g of benzene ( C_(6)H_(6) ) is 4.40^(@)C . The normal freezing point of benzene is 5.50^(@)C . What is the molal freezing point constant (@C//m) for benzene ?

When 20 g of napthanoic acid (C_(11)H_(8)O_(2)) is dissolved in 50 g of benzene (K_(f)=1.72 K kg/mol) a freezing point depression of 2 K is observed. The van't Hoff factor (i) is

An aqueous solution containing 12.48g of barium chloride in 1.0 kg of water boils at 373.0832 K. Calculate the degree of dissociation of barium chloride. [Given K_(b) for H_(2)O =0.52 Km^(-1) , Molar mass of BaCl_(2) =208.34 "g mol"^(-1) ]

The freezing point of an aqueous solution of KCN containing 0.1892 mol Kg^(-1) , the freezing point of the solution was found to be -0.530^(@)C . If the complex formation takes place according to the following equation: Hg(CN)_(2) , the freezing point of the solution was found to be -0.530^(@)C . If the complex formation takes place according to the following equation: Hg(CN)_2 +nKCN hArr K_n[Hg (CN)_(n+2)] what is the formula of the complex? [ K_(f)(H_(2)O) is 1.86 K kg mol^(-1) ]

RESONANCE ENGLISH-RANK BOOSTER-All Questions
  1. Consider equimolal aqueous solutions of NaHSO(4) and NaCl with DeltaT(...

    Text Solution

    |

  2. A solute S undergoes a reversible trimerization when dissolved in a ce...

    Text Solution

    |

  3. For a solution of 0.89 g of mercurous chloride in 50 g of HgCl(2)(l) ...

    Text Solution

    |

  4. Consider the following statements and arrange in order of true/false a...

    Text Solution

    |

  5. The vapour pressure of two miscible liquids A and B are 300 and 500 mm...

    Text Solution

    |

  6. Consider the following system. Three different aqueous solution each...

    Text Solution

    |

  7. 2.25 g of a Non volatile substance dissolved in 250 g of C6H6.This sol...

    Text Solution

    |

  8. Which of following statements are incorrect about Henry's law ?

    Text Solution

    |

  9. In which of the following pairs of solutions will the values of the va...

    Text Solution

    |

  10. V.P. of solute containing 6gm of non volatile solute in 180gm of water...

    Text Solution

    |

  11. Two liquids A and B form an ideal solution.The solution has a vapour p...

    Text Solution

    |

  12. Statement-1 : Perfectly ideal solution is not possible with respect to...

    Text Solution

    |

  13. Statement-1 : When a cell is placed in hypertonic solution, it shrinks...

    Text Solution

    |

  14. Statement-1 : The difference in the boiling points of equimolar soluti...

    Text Solution

    |

  15. Statement-1 : When 'a' ML of a 0.1 molal urea solution is mixed with a...

    Text Solution

    |

  16. A mixture of NO2 and N2O4 has a vapour density of 38.3 at 300K. What i...

    Text Solution

    |

  17. How many unpaired electrons are there in the electronic structure for ...

    Text Solution

    |

  18. Which of the following is not a member of 3d-transition series ?

    Text Solution

    |

  19. The pressure of two pure liquid A and B which form an ideal solutions ...

    Text Solution

    |

  20. The pressure of two pure liquid A and B which form an ideal solutions ...

    Text Solution

    |