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The pressure of two pure liquid A and B ...

The pressure of two pure liquid A and B which form an ideal solutions are 400 mm Hg and 800 mm Hg respectively at temperature T.A liquid containing 3:1 molar composition pressure can be varied.The solutions is slowly vapourized at temperature T by decreasing the applied pressure starting with a pressure of 760 mm Hg.A pressure gauge (in mm) Hg is connected which give the reading of pressure applied.
The reading of pressure Gauge at bubble point is

A

500

B

600

C

700

D

None

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the pressure gauge reading at the bubble point of a solution containing two liquids A and B that form an ideal solution. Here are the steps to arrive at the solution: ### Step-by-Step Solution: 1. **Identify Given Data:** - Vapor pressure of pure liquid A, \( P^0_A = 400 \, \text{mm Hg} \) - Vapor pressure of pure liquid B, \( P^0_B = 800 \, \text{mm Hg} \) - Molar composition of the solution: \( n_A : n_B = 3 : 1 \) 2. **Calculate Mole Fractions:** - The total moles in the solution can be expressed as \( n_A + n_B = 3 + 1 = 4 \). - Mole fraction of A, \( x_A = \frac{n_A}{n_A + n_B} = \frac{3}{4} = 0.75 \). - Mole fraction of B, \( x_B = \frac{n_B}{n_A + n_B} = \frac{1}{4} = 0.25 \). 3. **Apply Raoult's Law:** - According to Raoult's Law, the total vapor pressure \( P \) of the solution can be calculated using: \[ P = P^0_A \cdot x_A + P^0_B \cdot x_B \] - Substituting the values: \[ P = (400 \, \text{mm Hg} \cdot 0.75) + (800 \, \text{mm Hg} \cdot 0.25) \] 4. **Calculate Total Pressure:** - Calculate each term: \[ P = 300 \, \text{mm Hg} + 200 \, \text{mm Hg} = 500 \, \text{mm Hg} \] 5. **Determine the Bubble Point Pressure:** - The bubble point is the pressure at which the first bubble of vapor forms. This occurs at the total vapor pressure calculated above. - Therefore, the reading of the pressure gauge at the bubble point is: \[ \text{Pressure at bubble point} = 500 \, \text{mm Hg} \] ### Final Answer: The reading of the pressure gauge at the bubble point is **500 mm Hg**.

To solve the problem, we need to determine the pressure gauge reading at the bubble point of a solution containing two liquids A and B that form an ideal solution. Here are the steps to arrive at the solution: ### Step-by-Step Solution: 1. **Identify Given Data:** - Vapor pressure of pure liquid A, \( P^0_A = 400 \, \text{mm Hg} \) - Vapor pressure of pure liquid B, \( P^0_B = 800 \, \text{mm Hg} \) - Molar composition of the solution: \( n_A : n_B = 3 : 1 \) ...
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