`{:("Column-I","Column-II"),("electrolyte","I(van't off factor)"),((A)"Urea, Glucose, Fructose", (p)"1:0.8:1"),((B)NaCl"," MgCl_2","K_2SO_4,(q)"1:2:3"),((C )Al_2(SO_4)_3 Na_3PO_4"," K_4[Fe(CN)_6],(r)"1:1:1"),((D)"Glucose,"NaCl","CaCl_2,(s)"2:3:3"):}`

Explanation

To solve the problem, we need to match the electrolytes from Column-I with their corresponding van't Hoff factors from Column-II. Let's analyze each electrolyte step by step.

### Step 1: Analyze Electrolyte A (Urea, Glucose, Fructose)
- **Type**: Non-electrolytes
- **Dissociation**: These do not dissociate in solution.
- **Van't Hoff Factor (i)**: For non-electrolytes, i = 1.
- **Ratio**: Since all three are non-electrolytes, the ratio is 1:1:1.

**Match**: A corresponds to (r) 1:1:1.

### Step 2: Analyze Electrolyte B (NaCl, MgCl2, K2SO4)
- **NaCl**: Dissociates into Na⁺ and Cl⁻ → 2 ions.
- **MgCl2**: Dissociates into Mg²⁺ and 2 Cl⁻ → 3 ions.
- **K2SO4**: Dissociates into 2 K⁺ and SO₄²⁻ → 3 ions.
- **Van't Hoff Factors**:
- NaCl: i = 2
- MgCl2: i = 3
- K2SO4: i = 3
- **Ratio**: 2:3:3.

**Match**: B corresponds to (s) 2:3:3.

### Step 3: Analyze Electrolyte C (Al2(SO4)3, Na3PO4, K4[Fe(CN)6])
- **Al2(SO4)3**: Dissociates into 2 Al³⁺ and 3 SO₄²⁻ → 5 ions.
- **Na3PO4**: Dissociates into 3 Na⁺ and PO₄³⁻ → 4 ions.
- **K4[Fe(CN)6]**: This is a complex ion and dissociates into 4 K⁺ and 1 [Fe(CN)6]⁴⁻ → 5 ions.
- **Van't Hoff Factors**:
- Al2(SO4)3: i = 5
- Na3PO4: i = 4
- K4[Fe(CN)6]: i = 5
- **Ratio**: 5:4:5. Dividing by 5 gives us 1:0.8:1.

**Match**: C corresponds to (p) 1:0.8:1.

### Step 4: Analyze Electrolyte D (Glucose, NaCl, CaCl2)
- **Glucose**: Non-electrolyte → i = 1.
- **NaCl**: Dissociates into Na⁺ and Cl⁻ → 2 ions.
- **CaCl2**: Dissociates into Ca²⁺ and 2 Cl⁻ → 3 ions.
- **Van't Hoff Factors**:
- Glucose: i = 1
- NaCl: i = 2
- CaCl2: i = 3
- **Ratio**: 1:2:3.

**Match**: D corresponds to (q) 1:2:3.

### Summary of Matches
- A → (r) 1:1:1
- B → (s) 2:3:3
- C → (p) 1:0.8:1
- D → (q) 1:2:3

### Final Answer
- A - r
- B - s
- C - p
- D - q

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