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The vapour pressure of fluorobenzene at ...

The vapour pressure of fluorobenzene at `t^(@)C` is given by the equation
log `p(mm Hg)=7.0-(1250)/(t+220)`
Calculate the boiling point of the liquid in `.^(@)C` if the external (applied) pressure is `5.26%` more than required for normal boiling point. (log `2=0.3`)

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Verified by Experts

The correct Answer is:
85
`1.0526xx760=p_(ext)`
`p_(ext)=799.976=800` Torr
`:. "log" 800=7-1250/(t+220)`
`implies 2.9=7-1250/(t+220)impliest=84.878^@C`
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